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15n^2-1n-6=0
a = 15; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·15·(-6)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-19}{2*15}=\frac{-18}{30} =-3/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+19}{2*15}=\frac{20}{30} =2/3 $
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